BIOB51 Midterm 2 Review
End
of Chapter Textbook Questions (Assigned in Lecture)
Chapter
1
5. The idea behind multidrug therapy
for HIV is to increase the number of mutations required for resistance and thus
reduce genetic variation in the viral population for survival in the presence
of drugs. Could we achieve the same effect by using antiretroviral drugs in
sequence instead of simultaneously? Why or why not?
No, we
could not achieve the same result if we administer the drugs in a sequence. The
unfortunate result would likely be development of resistance to all the drugs.
This is because the HIV population would only have to develop resistance for
one drug at a time, which is quite easy for it to do. The key to multiple drug
therapy is that the drugs are given simultaneously, so that HIV virions must
have four or five simultaneous mutations (one for each drug) to survive. Even
with HIV's high mutation rate and large population size, the simultaneous
occurrence of multiple resistance mutations in one virion is unlikely.
17. Question 5 concerned treating HIV by
using multiple drugs sequentially instead of simultaneously. For a clinical
trial comparing these strategies, see: Gulick, R. M., J. W. Mellors, et al.
1998. Simultaneous vs sequential initiation of therapy with Indinavir,
Zidovudine, and Lamivudine for HIV-1 infection: 100-week follow-up. JAMA 280:
35.
Chapter
2
2. Consider
the experiment described in Section 2.1 in which Ted Garland and colleagues
bred mice to run long distances on exercise wheels. We presented the results as
evidence that two dozen generations of selective breeding had altered the
experimental population. How does the control strain support this
interpretation? If Garland had simply compared the behavior of the 24th
experimental generation to the behavior of the first experimental generation,
would the evidence for evolution be as strong? Explain.
Strong
evidence of evolution is seen in the results that come from selective breeding.
In the Garland et al. experiment on mice, microevolution could be observed
after only 24 generations of selection. The experimental design and procedure
was designed to measure the effect of selection and the change of the
population. From a large population of mice, the researchers chose high-runner
lines and control lines, each with 10 mated pairs. They needed to keep track of
each generation in the experiment, because they selected a male and female
which run the greatest distance, to produce the next generation. On the
contrary, the control strains had male and female pairs chosen at random in
each generation. Female mice from the selected lineages ran almost three times
faster than the control mice. This is direct evidence that population and
species change over time.
Chapter
3
8(Part
1).
Describe three major objections to Darwin’s theory in the 19th century that
were eventually resolved by discoveries by other scientists in the 20th
century.
Three
major objections to Darwin's theory in the 19th century were: there is not enough variability
for evolution to continue for very long; new traits would disappear by
"blending" with other traits; and, the earth's temperature implies
that the earth is too young for evolution to have occurred. These were
resolved by the discoveries, respectively, of mutation, genes, and
radioactivity.
Chapter 4
9. What is
homoplasy? Why does homoplasy make it more challenging to estimate evolutionary
history?
Homoplasy
is defined as a similarity in traits that is not due to inheritance (not
derived) from a common ancestor. Homoplasy is misleading because it makes
species that are not closely related appear as if they are closely related. If
the genetic and developmental basis of a morphological trait is known, then
researchers can distinguish homology from homoplasy. Morphological traits can
also be measured in fossil species. Compared to morphological traits, DNA
sequence data are relatively easy to acquire in large amounts, but can be
subject to extensive homoplasy.
Chapter
5
17.
Chromosome
number can evolve by smaller-scale changes than duplication of entire
chromosome sets. For example, domestic horses have 64 chromosomes per diploid
set while Przewalski’s horse, an Asian subspecies, has 66. Przewalski’s horse
is thought to have evolved from an ancestor with 2n = 64 chromosomes.
The question is: Where did its extra chromosome pair originate? It seems
unlikely that an entirely new chromosome pair was created from scratch in
Przewalski’s horse. To generate a hypothesis explaining the origin of the new
chromosome in Przewalski’s horse, examine the adjacent figure. The drawing at
right shows how certain chromosomes synapse in the hybrid offspring of a
domestic horse–Przewalski’s horse mating (Short et al. 1974). The remaining
chromosomes show a normal 1:1 pairing. Do you think this sort of gradual change
in chromosome number involves a change in the actual number of genes present?
The
most likely explanation is that the long chromosome found in domestic horses
split into two pieces in the ancestor of Przewalski's horse. If the two smaller
segments still synapse with the long chromosome during matings between hybrids,
then it is likely that gene number and order is unchanged.
20.
Figure
5.12 presented evidence that people with certain genotypes for the serotonin
transporter gene are more sensitive to maltreatment during childhood. For an
exploration of possible benefits associated with the sensitive genotype, see:
Homberg, J. R., and K. P. Lesch. 2011. Looking on the bright side of serotonin
transporter gene variation. Biological Psychiatry 69: 513–519.
Chapter
6
1. List
the five conditions that must be true for a population to be in Hardy–Weinberg
equilibrium. Why is it useful to know the conditions that prevent evolution?
For each condition, specify whether violation of that assumption results in
changes in genotype frequencies, allele frequencies, or both.
The five conditions are: no selection,
no mutation, no migration, no chance events (also can be stated as infinite
population size, or no genetic drift), and random mating. Violation of selection, mutation, migration, and/or chance events
will result in changes in allele frequencies and genotype frequencies in the
population. Violation of random mating—but not the others—will result in
changes in genotype frequencies but not in allele frequencies.
Textbook
Questions (Assigned in Tutorial)
Chapter
3
1.
In everyday English, the word adaptation
means an adjustment to environmental conditions. How is the evolutionary
definition of adaptation different from the everyday English sense?
The everyday meaning of "adaptation" refers to a
change that occurs in a single individual's lifetime, while the evolutionary
meaning refers to a trait that has developed via natural selection over many generations. An evolutionary adaptation is also
defined strictly in terms of
relative reproductive fitness, while the everyday meaning can refer to
changes that do not necessarily affect reproduction
2.
a. Describe
Darwin’s four postulates in your own words. What would have happened in the
snapdragon experiment if any of the four had not been true? b. If
Darwin’s four postulates are true for a given population, is there any way that
evolution cannot happen? What does this imply about whether evolution is or is
not occurring in most populations today?
a.
The four postulates are, briefly: variation exists,
the variation is heritable, survival and reproduction are not equal, and
survival and reproduction are not random. In the snapdragon experiment, if there had been no
variation, all flowers would have been the same color. If variation had not
been heritable, the colors of the best-reproducing plants would not have been
passed to their offspring. If there had not been unequal survival and
reproduction, all plants would have attracted equal numbers of bees and produced
equal numbers of seeds. If survival and reproduction had been random, some
plants would have had more bee visits and produced more seeds than other
plants, but the difference would not be related to plant color. In any of these
four cases, the snapdragon population would not have evolved.
b.
If the four
postulates are true, a population is virtually certain to evolve unless
selection is extremely weak and genetic drift is very strong. Since the four
postulates are almost always true, virtually all populations of organisms are
evolving today, at least with regard to some genetic loci.
4.
According to the text, it is correct to
claim that most finches died from starvation during the 1977 drought because
“there was a strong correspondence between population size and seed
availability.” Do you accept this hypothesis? If so, why don’t the data in
Figure 3.13 show a perfect correspondence between when seed supply started
falling and when population size started to drop?
The claim that the vanished finches probably died of starvation is
certainly reasonable given the data in Figure 3.13 and the absence of obvious
other causes such as increased predation or disease. The graphs in Figure 3.13
show that most small, soft seeds disappeared between about July and October of 1976,
the same time that the bird population began to decline. Seeds were still
abundant at first, but they were predominantly large seeds. Then, even the
large seeds began disappearing, and the bird population continued to decline
sharply. The birds did not all die instantaneously because it takes time for an
animal to starve to death, and some individuals were likely able to scratch for
the few remaining small seeds for several months before succumbing to
starvation.
5.
A common creationist criticism of the finch
study is, “But it’s just a little change in beak shape. Nothing really new has
evolved.” Or put a different way, “It’s just microevolution and not
macroevolution.” The finch team continues to spend a great deal of effort on
their project— traveling thousands of miles to the remote Galápagos every year,
just to try to band an entire population of birds and all their nestlings and
measure their bills. How would you respond to the creationists’ criticisms? Do
you think the ongoing 30-year-effort of the finch bill project has been
worthwhile? Is it useful to try to document microevolution, and does it tell us
anything about how macroevolution might work?
Many
answers are possible. Though it may be "just" microevolution, the
shape of a bird's bill is not a minor feature for the bird—it is the bird's one
and only food-handling tool. Furthermore, microevolution and macroevolution are
not a dichotomy, macroevolution is simply microevolution carried out for a long
time. The changes that most laypeople would consider "macroevolution"
typically require hundreds of thousands of years to evolve, so it is not
logical to expect to observe them in a single field study. Evolutionary
biologists generally regard long-term studies of microevolution as highly informative
for learning how natural selection happens in a natural environment, and for a
close-up look at the causes of small changes that, eventually, can add up to
macroevolution.
Chapter
4
5.
What is a synapomorphy?
Synapomorphy is a characteristic that is
shared by two or more species and also derived. This means that it was modified
in a common ancestor and then inherited by the descendant species.
9. What is homoplasy? Why does homoplasy make it
more challenging to estimate evolutionary history?
Homoplasy is defined as a similarity in traits that is not due to
inheritance (not derived) from a common ancestor. Homoplasy is misleading
because it makes species that are not closely related appear as if they are
closely related. If the genetic and developmental basis of a morphological
trait is known, then researchers can distinguish homology from homoplasy.
Morphological traits can also be measured in fossil species. Compared to
morphological traits, DNA sequence data are relatively easy to acquire in large
amounts, but can be subject to extensive homoplasy.
Chapter
5
1.
What is the difference between genetic
variation, environmental variation, and genotype-by-environment interaction?
Give examples of each. Try to think of potential examples not covered in this
chapter.
Genetic variation is
based on differences in alleles (versions of a gene) and ultimately the entire
genomes, among the individuals. Genetic variation is necessary for evolution,
since these differences are encoded and transmitted from one generation to the
next. For example, genetic variation in a blood type
gene in humans, results in four different phenotypes. In this case, three
different alleles of one gene are: I A, I B, i (where I A and IB are
codominant, while allele i is recessive to either one). Different combinations
of these alleles produce four possible phenotypes: A, B, AB and O blood types,
with different frequencies in different parts of the world.
Environmental
variation is based on the differences produced when same genotypes are exposed
to different environments. This usually happens because certain environments
might alter gene expression. For example
one genotype in a species of plants, often produces different sizes of mature
plants, when grown in the different altitudes or with different soil nutrients.
Similarly, dark pigmentation on the tips of ears and paws of Siamese cats
develops in certain latitudes with colder temperatures. Many additional
examples of traits that could vary a great deal under environmental changes are
found in quantitative traits.
Genotype by
environment variation is based on both differences in the genomes and ways that
environment affects the phenotypes. When one genotype develops different
phenotypes in different environments, we could say that this genotype exhibits
phenotypic plasticity. For example,
a change from asexual to sexual reproduction, based on the amount of nutrients,
predation or parasitism. Phenotypic plasticity can also evolve.
5.
Consider the nucleotide sequence
TGACTAACGGCT. Transcribe this sequence into mRNA. Use the genetic code to
translate it into a string of amino acids. Give an example of a point mutation,
an insertion, a deletion, a frameshift mutation, a synonymous substitution, a
nonsynonymous substitution, and a nonsense mutation. Which of your examples
seem likely to dramatically influence protein.
Example answer:
DNA: TGACTAACGGCT
RNA: ACUGAUUGCCGA
Polypeptide: Threonine-Aspartic Acid-Cysteine-Arginine
A point mutation, such as T to G in the DNA strand, gives CCU for the first codon and that would replace amino acid threonine with proline.
An insertion or a deletion would cause a frame-shift. For example, a deletion in DNA: TGACTAACGGCT, leaves mRNA sequence as: ACGAUUGCCGA and the polypeptide would be:
Threonine-Isoleucine-Cysteine. Duplication/insertion of a single base also causes a frameshift, since each codon has three bases. This also affects the rest of the sequence.
If the polypeptide change remains the same due to a change where DNA has one base-pair change, yet same amino acid remains in its place, we use the term synonymous substitution. For example ACU codes for Threonine, but if there is a silent substitution of ACU to ACC, ACG or ACA, the amino acid will remain in its place. The protein will function the same, with such mutation. A silent site mutation does not change the amino acid specified by a codon; a replacement mutation does.
If there is a substitution of one amino acid to another, due to the base-pair change in DNA and RNA, we use the term non-synonymous substitution.
A nonsense mutation will bring a stop codon, instead of an amino acid. Example is UUA for Leucine, might become a stop codon with one base change (UGA). Nonsense mutations probably affect the carrier most dramatically, because they do not allow polypeptide chain to grow.
DNA: TGACTAACGGCT
RNA: ACUGAUUGCCGA
Polypeptide: Threonine-Aspartic Acid-Cysteine-Arginine
A point mutation, such as T to G in the DNA strand, gives CCU for the first codon and that would replace amino acid threonine with proline.
An insertion or a deletion would cause a frame-shift. For example, a deletion in DNA: TGACTAACGGCT, leaves mRNA sequence as: ACGAUUGCCGA and the polypeptide would be:
Threonine-Isoleucine-Cysteine. Duplication/insertion of a single base also causes a frameshift, since each codon has three bases. This also affects the rest of the sequence.
If the polypeptide change remains the same due to a change where DNA has one base-pair change, yet same amino acid remains in its place, we use the term synonymous substitution. For example ACU codes for Threonine, but if there is a silent substitution of ACU to ACC, ACG or ACA, the amino acid will remain in its place. The protein will function the same, with such mutation. A silent site mutation does not change the amino acid specified by a codon; a replacement mutation does.
If there is a substitution of one amino acid to another, due to the base-pair change in DNA and RNA, we use the term non-synonymous substitution.
A nonsense mutation will bring a stop codon, instead of an amino acid. Example is UUA for Leucine, might become a stop codon with one base change (UGA). Nonsense mutations probably affect the carrier most dramatically, because they do not allow polypeptide chain to grow.
7.
How many redheads live in a village of 250
people, where the frequency of red hair is 0.18?
If there are 250 people in the village and 18% of them have red
hair, there are 45 red heads in the village.
15. Suppose
a silent mutation occurs in an exon that is part of the gene for TAS2R38 in a
human. Has a new allele been created? Defend your answer.
A
silent mutation in the gene for TAS2R38 in human would create a new allele,
because the DNA sequence will be different, yet it might not have any
phenotypic effects, if the amino acids that are responsible for tasting PTC
remain the same.
Chapter
6
1. List the five
conditions that must be true for a population to be in Hardy–Weinberg
equilibrium. Why is it useful to know the conditions that prevent evolution?
For each condition, specify whether violation of that assumption results in
changes in genotype frequencies, allele frequencies, or both.
The five conditions are: no selection, no mutation, no
migration, no chance events (also can be stated as infinite population size, or
no genetic drift), and random mating. Violation of selection, mutation,
migration, and/or chance events will result in changes in allele frequencies
and genotype frequencies in the population. Violation of random mating—but not
the others—will result in changes in genotype frequencies but not in allele
frequencies.
2. Why was
it important that G. H. Hardy used variables in his mathematical treatment of
changes in population allele frequencies across generations? Would it have been
equally useful to simply work several more examples with different specific
allele frequencies?
The use of variables allowed Hardy to prove the general case:
that—given the five assumptions—any allele frequencies will stay in equilibrium.
Before this proof, it was not intuitively clear to most people that the
specific allele frequencies did not matter. As is often the case, general
proofs expressed mathematically can reveal important patterns that were not
always intuitively obvious beforehand.
3.
Name the phenomenon being described in
each of these (hypothetical) examples, and describe how it is likely to affect
allele frequencies in succeeding generations.
A)
Migration followed by natural selection. The frequency of the T allele is likely
to increase rapidly.
B) Migration followed by natural selection. The frequency of the T allele may increase, but only slowly, and perhaps not at all, due to the rarity of the T allele and the weakness of selection.
C) Frequency-dependent selection. The frequency of small males is likely to gravitate toward a stable equilibrium frequency, at which small and large males have identical fitness.
D) Under dominance. One allele will very likely go to fixation, and the other allele will be lost. Which allele is lost is likely to depend on where the initial allele frequencies are, relative to the unstable equilibrium point.
E) Heterozygote superiority, or over dominance. The frequency of the m allele is likely to gravitate toward a stable equilibrium frequency.
B) Migration followed by natural selection. The frequency of the T allele may increase, but only slowly, and perhaps not at all, due to the rarity of the T allele and the weakness of selection.
C) Frequency-dependent selection. The frequency of small males is likely to gravitate toward a stable equilibrium frequency, at which small and large males have identical fitness.
D) Under dominance. One allele will very likely go to fixation, and the other allele will be lost. Which allele is lost is likely to depend on where the initial allele frequencies are, relative to the unstable equilibrium point.
E) Heterozygote superiority, or over dominance. The frequency of the m allele is likely to gravitate toward a stable equilibrium frequency.
OA
1. An entire village of 500 people were tested for sensitivity for
bitter-tasting foods. How many people are non-tasters where frequency of
non-tasters in this population is 0.29?
500 x 0.29 = 145
2. If a mutational change occurs in the normal sequence 5' -
ATTATACACAGAGAGTTT -3' to change it to 5'- ATTATACACAGAGTTT -3' which
term best describes the mutation or possible cause?
Deletion
of AG
3. Use the table to answer the question. Which of the following is
the outgroup?
Presence (1) or Absence (0) of Hox Genes
Hox1
|
Hox2
|
Hox3
|
Hox4
|
Hox12
|
|
Mouse
|
1
|
1
|
1
|
1
|
1
|
Snail
|
1
|
1
|
1
|
1
|
0
|
Flatworm
|
1
|
1
|
1
|
1
|
0
|
Sea anemone
|
1
|
1
|
0
|
0
|
0
|
Sponge
|
0
|
0
|
0
|
0
|
0
|
Sponge
4. The Hardy-Weinberg term p gives:
Allele frequency
5. Black colour in horses is governed by homozygosity of the recessive
allele at the A locus: black coloured horses have aa while horses
with other nonblack colours may be AA or Aa at the same locus.
Assuming the alleles are at Hardy-Weinberg equilibrium, what best describes the
genotype frequency of black horses in a population of Arabian horses? 2pq?
6. Which of the following phrases best fits the term SNP?
Two
different nucleotides appear at the same position in genomic DNA from different
individuals
7. Socially parasitic ants form a group that includes S.
daguerrei, the ancestor of socially parasitic species and all its descendents:
____ .
Clade
8. The S . saevissima species group contains socially
polymorphic species which form a ____ group.
Monophyletic
9. At the level of the species, the mtDNA phylogeny excludes some of
the ancestors of this group: it is a _______ group.
Polyphyletic
10. A _______ based on morphological characters, is an evolutionary
hypothesis for the relationships between the S. saevissima species.
Phylogeny
11. This study confirmed that ___ originated once among these ants.
Polygyny
(multiple queens)
12. Among ______ S. invicta ants there are some colonies that
accept only one queen and other colonies that accept multiple queens
Socially
polymorphic
13. Choose all that apply to complete the sentence. Examples of homoplasy
include _____ .
A.
|
Spots on leopard
geckos and leopards
|
|
B.
|
Streamlined bodies in
dolphins and ichthyosaurs
|
|
D.
|
Bobbed tails in
bobcats and lynx
|
|
F.
|
Eyes on the top of
the head in caiman and hippos
|
14. Researchers studied snapdragon plants and their bumblebee
pollinators. The researchers found that after two generations white-flowered
snapdragon plants had higher reproductive success than did yellow-flowered
snapdragon plants. Which of the following statements about the role of
bumblebees should form part of their conclusion?
Bumblebees
are the agents of selection: they chose to pollinate the white-flowered plants
and this resulted in higher reproductive success for the white flowered
snapdragons.
15. Choose the best option to complete the sentence. If an
adaptation is a product of natural selection the trait will __________.
be a
heritable trait that raises the fitness of individuals more than any other
trait that has appeared in the species over evolutionary time.
16. Homozygosity at the recessive a locus gives albinism in
whales. Researchers counted the number of albino and the number of normally
pigmented whales in a population. The number of normally pigmented whales
divided by the total population gives:
Phenotype
frequency
1/15 ;2pq
|
17. Go to OMIM (see link in OA1 folder) type in 602421 to go to
Cystic Fibrosis. Scroll down on the 602421 cystic fibrosis page to find
"Allelic Variants" .0001 and find the information needed to identify
which of the options below would best complete the following sentence. In the
Saguenay-Lac-Saint-Jean region of Quebec De Braekeleer estimates that the
carrier rate is ____ which would correspond to ____ if the population is
at Hardy-Weinberg equilibrium.
18. On an island there are many cats with short tails. The alleles
for tailless are tightly linked to a short tandem repeat DNA marker.
Researchers sampled 150 cats identifying 60 homozygous for the wildtype
6-repeat STR; 90 short-tailed cats that were heterozygous for the wildtype
6-repeat STR allele but they did not find any cats homozygous for the 10-
repeat STR allele associated with tailless. What are the genotype
frequencies in this population? HINT: write out the genotypes. Chose all the
answers that apply.
a.
|
0.4 (6,6)
|
|
b.
|
0.6 (6,6)
|
|
c.
|
0.16 (10,10)
|
|
d.
|
0.4 (10,6)
|
|
e.
|
0.4 (10,10)
|
|
f.
|
0.6 (10,6)
|
Chapter 8
7. How can you identify an allele that has experienced recent strong
positive selection?
Ans) Loci that have been under
recent positive selection will usually be in linkage disequilibrium with nearby
neutral markers (indicate an allele of young age), and will be at relatively
high frequency for the allele's age.
8. Populations of rats exposed to
the poison warfarin rapidly evolve resistance. The gene for warfarin resistance
is located on rat chromosome 1. Michael Kohn and colleagues (2000) surveyed
rats in five German rat populations known to vary in their recent exposure to
warfarin and in their resistance. The researchers determined the genotype of
each rat at a number of marker loci near the warfarin resistance gene. For each
population, the researchers calculated the average heterozygosity (H) among the
marker loci, the fraction of loci that were out of Hardy–Weinberg equilibrium
(HWE), and the fraction of marker–locus pairs that were in linkage
disequilibrium (LD). Their results appear in Figure 8.32. Based on these graphs, rank the five
populations in order, from lowest to highest, for exposure to warfarin and
resistance. Explain your reasoning.
Ans) Strong positive selection tends to cause high linkage disequilibrium
and tends to lower heterozygosity. Therefore we can deduce that the x-axis must
start with low resistance on the left, and go to high resistance on the right.
The most resistant population should be WU, and the least resistant should be
LH
This deduction is correct: the most resistant rat population is WU,
followed by BK, PS, HT, and LH. In the original graphs, the x-axis goes from 0%
resistance on the left to 100% resistance on the right.
Chapter 9
1. Degree of antisocial behavior is a quantitative trait in human males.
Avshalon Caspi and colleagues (2002) used data on several hundred men to
investigate the relationship between antisocial behavior and two factors. The
first factor was genotype at the locus that encodes the enzyme monoamine
oxidase A (MAOA). MAOA acts in the brain, where it breaks down a variety of the
neurotransmitters nerve cells use to communicate with each other. The gene for
MAOA is located on the X chromosome. Due to genetic differences in the gene’s promoter,
some men have low MAOA activity and others have high MAOA activity. The second
factor was the experience of maltreatment during childhood. Based on a variety
of evidence, the researchers determined whether each man had experienced no
maltreatment, probable maltreatment, or severe maltreatment. The data are
summarized in Figure
9.34.
a. Is the variation among men in antisocial
behavior at least partly due to differences in genotype? Explain.
b. Is the variation among men in antisocial
behavior at least partly due to differences in environment? Explain.
c. Do men with different genotypes respond the
same way to changes in the environment? Explain.
d. Is antisocial behavior heritable? Explain.
e. Do these data influence your opinion about
how men who exhibit antisocial behavior should be treated
and/or punished?
Ans) A) The figure shows that variation in antisocial behavior is
correlated with differences in genotype. It is possible that the correlation is
due to some other factor (for example, certain genotypes may be more common in
certain ethnic groups, which may be exposed to certain environments). However,
if we leave that possibility aside, we can tentatively conclude that MAOA
genotype is associated with antisocial behavior.
B) Yes, because different levels of childhood maltreatment (an
environmental condition) are associated with different levels of antisocial
behavior. If there were no effect of environment, both lines would have a slope
of 0 (parallel to the x-axis).
C) Men with different genotypes respond in the same direction: for men in
both MAOA categories, increased maltreatment is associated with heightened
antisocial behavior. However, the strength of this effect is different in the
two groups. Men with the low MAOA activity genotype appear more strongly
influenced by environment than are men with the high MAOA activity genotype.
The line for men with low MAOA activity has a greater (steeper) slope than the
line for men with high MAOA activity, indicating a stronger effect of the
environment factor on the x-axis.
D) Yes. This means simply that some of the variation in antisocial
behavior is attributable to genotype.
E) The answer to this question is left to the reader.
4. Suppose you are telling your roommate that you learned in biology
class that within any given human population, height is highly heritable. Your
roommate, who is studying nutrition, says, “That doesn’t make sense, because
just a few centuries ago most people were shorter than they are now, clearly
because of diet. If most variation in human height is due to genes, how could
diet make such a big difference?” Your roommate is obviously correct that poor
diet can dramatically affect height. How do you explain this apparent paradox
to your roommate?
Ans) High heritability within a population does not mean that variation
between populations is due to genetic differences. If the populations differ in
an environmental factor, the variation between populations can be due entirely
to environment. In this case, your roommate is comparing height between two
populations (a medieval population versus a modern population) that differ in
dietary environment.
5. Now consider heritability in more general terms. Suppose heritability
is extremely high for a certain trait in a certain population.
a. First, can the trait be strongly affected by
the environment despite the high heritability value? To answer this question,
suppose that all the individuals within a certain population have been exposed
all their lives to the same level of a critical environmental factor. Will the
heritability value reflect the fact that the environment is very important?
b. Second, can the heritability value change if
the environment changes? To answer this question, imagine that the critical
environmental factor changes such that different individuals are now exposed to
different levels of this environmental factor. What happens to variation in the
trait in the whole population? What happens to the heritability value?
Ans) A) Yes, the trait may be
strongly affected by environment. But no matter how important the environment
could potentially be, if there is little variation in environment, the
heritability value will typically be very high.
B) Heritability values will often change if the environment changes.
Typically, if a formerly invariant environment begins to change, heritability
values will decrease.
Chapter 10 questions
4. What is an evolutionary trade-off? Why do they occur? Give two
examples. How does the occurrence of tradeoffs illuminate the general question
of whether all traits are adaptive?
Ans) A trade-off is a situation in which an increase the fitness of one
trait will inevitably lead to a decrease in fitness of another trait. This can
occur due to developmental constraints, or simply because organisms have a
limited pool of energy and cannot develop all traits to a maximum degree
simultaneously. Examples include testis size versus brain size in bats, and
flower size versus number of flowers in begonias. The occurrence of trade-offs
demonstrates that a particular trait can be adaptive in one context, yet the
same trait can be non-adaptive in a different context.
11. Suppose that fish were introduced into Lake Citadelpark, one of the
lakes De Meester studied. What do you predict will happen to phenotypic
plasticity in the Daphnia of Lake Citadelpark? Outline the observations you
would need to make to test your prediction.
Ans) A logical prediction is that Daphnia in Lake Citadelpark would
evolve greater phenotypic plasticity in phototactic behavior if fish were
introduced into the lake. To test this prediction, we could allow a number of
generations to pass, then repeat De Meester's experiment. We could then isolate
many individual genotypes and allow them to reproduce asexually in the
laboratory, producing many replicates of each genotype. Each genotype could
then be tested for phototactic behavior, both in water that had never had fish
in it, and also in water that came from the lake. If the prediction is correct,
then members of each genotype will show strong negative phototaxis in normal
(fish-inhabitated) lake water and much weaker negative phototaxis in water that
had never had fish in it.
OA 2 (ans still not 100%)
The neutral theory predicts that as a result of genetic drift the rate of accumulation of nonsynonymous substitutions will be slower because __________
ANS:
An article about
lizards in the Dominican Republic notes that lizards in the Greater Antilles are an example of
"replicated adaptive radiation". What is adaptive radiation?
ANS:
Splitting of group of
lizards into populations that became adapted to many different ecological
niches
The Q and D
genes are 20 map units apart: the recombination rate r= 0.2. In the cross Qd/ qD x qd/ qd what fraction of the progeny will be QD/ qd?
ANS:
A mating between two
related individuals is Consanguineous
The article titled
"Population genetics of the white phased spirit black bear of British
Columbia " written by Hedrick and Ritland was published in the journal
Evolution in the year 2012 ,volume 66 pages 305 – 313
The neutral theory predicts that as a result of genetic drift the rate of accumulation of nonsynonymous substitutions will be slower because __________.
ANS:
They are often deleterious mutations and are removed by natural selection
Fruit flies have gene
timeless with two allals: Is-tim and s-tim. How could researchers identify
whether the Is-tim allele has experienced recent strong positive selection at a
site in Italy called Novoli? Among the fruit flies from the Novoli population…
ANS: The Is-tim allele would be at high frequency and high linkage
disequilibrium with nearby marker loci
A gene D is linked to
its marker G. Linkage means … The genotype for the tightly linked loci on the
chromosome
Marker “G” is
characterized by three single nucleotide polymorphisms, the haplotype would be
… tendency for alleles at different loci on a chromosome to be inherited
together
Researchers tested
whether gene and marker locus were in linkage equilibrium within a population.
Linkage equilibrium is… tendency for genotypes at one locus to be randomly
distributed with respect to genotypes at another locus
Inbreeding is mating
among kin
The Q and D genes are
20 map units apart: recombination rate r = 0.2. In cross Qd/qD x qd/qd. What
fraction of progeny will be QD/qd?
10%
In a population of
mice at an interesting genetic locus for which the recessive m alleles do not
make a functional protein. If researchers estimate mutation rate to be
0.9x10^-4 and they know that the selection coefficient is 0.9, what is the equilibrium
frequency for the maintenance of alleles at this locus?
ANS:
Q = sqrt(u/s) u =
0.9x10^-4, s = 0.9
0.01
If the bear cub in
the article is not albino, but a white-phase bear because it has the same
genotype as a Kermode bear in Ritland and Marshall (2001), then the bear cub
will be heterozygous at Cys at codon 298 that codes for MC1R from its mother
and father.
ANS:
*In a plant
population linkage disequilibrium is complete between branch length locus (B)
and presence of a marker “e”. If the marker absence is “E” then what must be
true of this plant population?
ANS:
Branch length locus
and marker e are on different chromosomes?
*If a student was
working on an experimental population of pea plants. The student crossed plants
that were reddish-purple and gave long pollen to other plants that were pink
and gave round pollen and he wrote the genotypes of the plants in cross: R L /
r l x r l / r l. (Flower colour = R=reddish-purple, r = pink) and pollen shape
(L = long, r = round). Choose best option for completing sentence in his
notebook. If the two loci, flower colour and pollen shape, are not linked, l
would expect ____ of progeny of this cross to be R L / r l.
ANS:
75%
Among a population of 220 bears on a small island the frequency of the MC1R298Cys was 0.1 and the population was at Hardy Weinberg equilibrium. Then 30 black bears migrated to the small island from the mainland where the MC1R298Tyr was fixed. What are the new allele frequencies of the admixed population? Choose all the frequencies needed to complete the sentence. Among the admixed island population the f(MC1R298Tyr )= p= ______ and f(MC1R298Cys) = q= ________ , the new allele frequencies indicate that the island population has evolved as a consequence of the migration.
ANS:
0.01, 2, 0.81, 0.18, 0.088, 0, 1, 0.912
Researchers
analyzed genotypes of all 30 bunnies from a small island population and found 5
of them were genotype AG: they were heterozygous at a SNP in the ASIP gene. If
frequency of A allele of SNP is 0.33 what is fixation index of population?
ANS:
0.11, 1, 0.44, 0.63, 0.18
Is the black horse question really 2pq? Why?
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